Capacitor EnergyFree online science calculator — instant results, no sign-up

Calculate the energy stored in a capacitor (E = ½CV²).

Inputs

µF
V
Stored energy
0.072 J
In millijoules72 mJ

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About the Capacitor Energy

The Capacitor Energy calculator calculates the electrical energy stored in a capacitor using its capacitance in microfarads and the voltage across its terminals. It applies E = ½CV² and reports the result in joules and millijoules. With the default inputs of 1000 µF and 12 V, the stored energy is 0.072 J, or 72 mJ.

Capacitance (µF)
The capacitor's capacitance, entered in microfarads (µF), indicates its ability to store charge per unit voltage and defaults to 1000 µF.
Voltage (V)
The potential difference across the capacitor's terminals, entered in volts (V), defaults to 12 V.

Formula and method

C_F = C_µF × 10⁻⁶; E_J = ½ × C_F × V²; E_mJ = E_J × 1000.
  • C_µFCapacitance entered in microfarads (µF).
  • C_FCapacitance converted to farads (F).
  • VVoltage across the capacitor, in volts (V).
  • E_JStored electrical energy in joules (J).
  • E_mJThe same stored electrical energy expressed in millijoules (mJ).

Convert the capacitance from microfarads to farads, then multiply it by the square of the voltage and by one-half. For the default inputs, 1000 µF × 10⁻⁶ = 0.001 F, so E = ½ × 0.001 × 12² = 0.072 J. Multiply by 1000 to express this as 72 mJ.

Worked example

These are the calculator's starting values and the results it actually produces for them.

Inputs

  • Capacitance1000 µF
  • Voltage12 V

Results

  • Stored energy0.072 J
  • In millijoules72 mJ

How to use the Capacitor Energy

  1. 1Enter the capacitance in microfarads; keep 1000 µF to reproduce the default example.
  2. 2Enter the voltage actually across the capacitor; keep 12 V for the default example.
  3. 3Calculate the energy using E = ½CV², with capacitance converted to farads.
  4. 4Read the stored-energy output in joules: the default example gives 0.072 J.
  5. 5Read the millijoule output for the same energy on a smaller unit scale: the default example gives 72 mJ.

Reading your result

The 'Stored energy' row gives the capacitor's electrical energy in joules; with 1000 µF at 12 V, it reads 0.072 J. The 'In millijoules' row expresses exactly the same energy as 72 mJ, since 1 J = 1000 mJ. These are energy values, not power ratings or estimates of how long the capacitor can operate a load.

Limitations

The formula assumes an ideal capacitor with constant capacitance. Real capacitance can vary with tolerance, temperature, and applied voltage, and leakage and internal resistance reduce energy delivered to a load. The result does not predict discharge time, peak current, or charging losses. Use nonnegative capacitance and the actual terminal voltage; the capacitor's voltage rating is a limit, not necessarily its operating voltage. This calculation does not establish electrical safety: observe voltage and polarity ratings and use appropriate discharge procedures.

Common questions

Why must 1000 µF be converted before using E = ½CV²?+

The formula gives energy in joules when capacitance is in farads and voltage is in volts. Therefore, 1000 µF becomes 0.001 F before calculating ½ × 0.001 × 12² = 0.072 J.

Should I enter the capacitor's rated voltage or its measured voltage?+

Enter the voltage actually across its terminals. The rated voltage is the manufacturer's operating limit; using it would estimate energy at that voltage rather than the energy currently stored.

How does voltage affect the stored energy compared with capacitance?+

Energy is proportional to capacitance but to the square of voltage. At unchanged voltage, doubling capacitance doubles energy; at unchanged capacitance, doubling voltage quadruples energy, provided the capacitor remains within its ratings.

Can a load receive all 72 mJ from the default capacitor?+

The 72 mJ result is the ideal stored energy at 1000 µF and 12 V. A real load usually receives less because of losses and any energy left when discharge stops. For constant capacitance, the ideal energy released between initial and final voltages is ½C(V_initial² − V_final²), with C in farads.

Does the calculator save my information?+

Calculations run in your browser. While signed in, inputs and results are automatically recorded in account history; saving a result creates a separate saved record.

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Results are estimates for informational purposes and are not financial, medical or legal advice.